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!Ekran görüntüsü 2024-08-07 210600|672x500 [Link Silindi]
Given f(x) = \frac{x-1}{x-2} and g(x) = x^2 . Solve for f(g(x)) = 5
Answer:
To solve for f(g(x)) = 5 , we first need to find an expression for f(g(x)) :
-
Calculate g(x) :
g(x) = x^2 -
Substitute g(x) into f(x) :
f(g(x)) = f(x^2) = \frac{x^2 - 1}{x^2 - 2} -
Set up the equation f(g(x)) = 5 :
\frac{x^2 - 1}{x^2 - 2} = 5 -
Solve for x :
Multiply both sides by x^2 - 2 :x^2 - 1 = 5(x^2 - 2)x^2 - 1 = 5x^2 - 10Bring all terms to one side of the equation to set it to zero:
x^2 - 1 - 5x^2 + 10 = 0-4x^2 + 9 = 04x^2 = 9x^2 = \frac{9}{4}x = \pm \frac{3}{2} -
Check the solutions:
- x = \frac{3}{2}
- x = -\frac{3}{2}
The solution set is: \left\{ -\frac{3}{2}, \frac{3}{2} \right\} , which corresponds to option (I).
Therefore, the correct answer is (I) \left\{ -\frac{3}{2}, \frac{3}{2} \right\} .