0,2 mol H₂ ve 0,4 mol O, gazlarının tam verimle tepkimesinden su oluşmaktadır. Bu tepkimeyle ilgili aşağıdaki soruları cevaplayınız. a) Sınırlayıcı madde hangisidir? b) Hangi maddeden kaç mol artar? c) Kaç gram su oluşur? (H: 1, O: 16)
@sorumatikbot
a) Sınırlayıcı madde hangisidir?
To determine the limiting reagent, we need to compare the mole ratios of the reactants involved in the reaction. The balanced equation for the reaction is:
2H₂ + O₂ → 2H₂O
From the given information, we have 0.2 mol of H₂ and 0.4 mol of O₂.
The mole ratio between H₂ and O₂ is 2:1.
Let’s calculate the moles of H₂O that can be formed by using both H₂ and O₂:
- Moles of H₂O from 0.2 mol H₂ = 0.2 mol H₂ * (2 mol H₂O / 2 mol H₂) = 0.2 mol H₂O
- Moles of H₂O from 0.4 mol O₂ = 0.4 mol O₂ * (2 mol H₂O / 1 mol O₂) = 0.8 mol H₂O
As we can see, the moles of H₂O formed from 0.2 mol of H₂ is 0.2 mol, while the moles of H₂O formed from 0.4 mol of O₂ is 0.8 mol. Therefore, the limiting reagent is H₂ and it is completely consumed in the reaction.
b) Hangi maddeden kaç mol artar?
Since H₂ is the limiting reagent, it will be completely consumed in the reaction. Therefore, the amount of H₂ remaining after the reaction will be zero. The increase in moles of H₂O is equal to the moles of H₂ consumed.
From the stoichiometry of the balanced equation, we can see that for every 2 moles of H₂ consumed, 2 moles of H₂O are formed. Therefore, the increase in moles of H₂O is also 0.2 mol.
c) Kaç gram su oluşur? (H: 1, O: 16)
To calculate the mass of water formed, we need to use the molar mass of water, which is 18 g/mol (H₂O = 2(1 g/mol) + 16 g/mol).
The moles of water formed is given as 0.2 mol. Using this information, we can calculate the mass of water:
Mass of water = Moles of water * Molar mass of water
= 0.2 mol * 18 g/mol
= 3.6 g
Therefore, 3.6 grams of water will be formed in the reaction.