Bir bölme işleminde kalan 5tir bölen yazılabilecek en küçük sayı kaçtır?
Kubra_Ozer’s Question: Bir bölme işleminde kalan 5’tir; bölen yazılabilecek en küçük sayı kaçtır?
Answer:
In division, when dividing one integer by another, there are three main elements: the dividend (the number being divided), the divisor (the number by which the dividend is divided), and the remainder (the amount left after division).
The general form of division can be represented as:
Dividend = (Divisor × Quotient) + Remainder
Given that the remainder is 5, we need to find the smallest possible value for the divisor such that the remainder is valid. The rule for the remainder is that it must be less than the divisor. Thus, if the remainder is 5, the divisor must be greater than 5.
Steps to Determine the Smallest Divisor:
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Understand the Rule:
- The remainder must always be less than the divisor in a division operation. Therefore, the smallest the divisor can be is any number greater than 5.
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Identify the Smallest Possible Divisor:
- Since the remainder cannot be greater than the divisor and must be less, the smallest allowable divisor when the remainder is exactly 5, is 6.
Final Answer:
The smallest divisor for which the remainder can be 5 is 6.