# Trigonometri 2 sorusu

**URL:** <https://sorumatik.co/t/trigonometri-2-sorusu/60567>\
**Category:** 12.Sınıf Matematik\
**Created:** [Aralık 22, 2023, 5:38ös UTC](https://sorumatik.co/t/trigonometri-2-sorusu/60567 "2023-12-22T17:38:51Z")\
**Posts on this page:** 3\
**Page:** 1

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**Author:** ![Merve\_Nur\_Gülhan](https://sorumatik.co/user_avatar/sorumatik.co/merve_nur_g%C3%BClhan/32/22273_2.png) [@Merve\_Nur\_Gülhan](https://sorumatik.co/u/Merve_Nur_G%C3%BClhan)\
**Post date:** [Aralık 22, 2023, 5:38ös UTC](https://sorumatik.co/t/trigonometri-2-sorusu/60567/1 "2023-12-22T17:38:52Z")

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Sin65.cos5-sin5.cos65

@sorumatikbot

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**Author:** ![Sorumatik\_Ogretmen](https://sorumatik.co/user_avatar/sorumatik.co/sorumatik_ogretmen/32/30517_2.png) [@Sorumatik\_Ogretmen](https://sorumatik.co/u/Sorumatik_Ogretmen)\
**Post date:** [Aralık 22, 2023, 5:39ös UTC](https://sorumatik.co/t/trigonometri-2-sorusu/60567/2 "2023-12-22T17:39:07Z")

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To solve the expression Sin65.cos5-sin5.cos65, we need to use trigonometric identities and the values of sine and cosine for specific angles.

First, we can simplify the expression using the difference-of-angles identity for sine:

sin(A - B) = sin(A)cos(B) - cos(A)sin(B)

In this case, A = 65 and B = 5, so we have:

sin(65 - 5) = sin(65)cos(5) - cos(65)sin(5)

Now, we need to determine the values of sin(65) and cos(65).

Using a calculator or trigonometric tables, we find that sin(65) ≈ 0.9063 and cos(65) ≈ 0.4226.

Similarly, we find that sin(5) ≈ 0.0872 and cos(5) ≈ 0.9962.

Now, we can substitute these values into the expression:

sin(65)cos(5) - cos(65)sin(5) ≈ (0.9063)(0.9962) - (0.4226)(0.0872)

≈ 0.9030 - 0.0369

≈ 0.8661

So, the value of Sin65.cos5-sin5.cos65 is approximately 0.8661.

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**Author:** ![Ozkanhoca](https://sorumatik.co/user_avatar/sorumatik.co/ozkanhoca/32/133_2.png) [@Ozkanhoca](https://sorumatik.co/u/Ozkanhoca)\
**Post date:** [Aralık 22, 2023, 7:17ös UTC](https://sorumatik.co/t/trigonometri-2-sorusu/60567/3 "2023-12-22T19:17:34Z")

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Verilen açılım sin(65-5) açılımıdır sin60=kök3/2 dir @Merve\_Nur\_Gülhan