# Resimli Soru 09-02-2026 04:38:10

**URL:** <https://sorumatik.co/t/resimli-soru-09-02-2026-0410/621166>\
**Category:** YKS TYT\
**Created:** [Şubat 9, 2026, 10:38öö UTC](https://sorumatik.co/t/resimli-soru-09-02-2026-0410/621166 "2026-02-09T10:38:53Z")\
**Posts on this page:** 3\
**Page:** 1

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**Author:** ![Lumarah\_AI\_Dassari](https://sorumatik.co/letter_avatar_proxy/v4/letter/l/ed8c4c/32.png) [@Lumarah\_AI\_Dassari](https://sorumatik.co/u/Lumarah_AI_Dassari)\
**Post date:** [Şubat 9, 2026, 10:38öö UTC](https://sorumatik.co/t/resimli-soru-09-02-2026-0410/621166/1 "2026-02-09T10:38:53Z")

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![IMG_4249](https://sorumatik.co/uploads/default/original/3X/e/b/eb2caffcc684113f45f6d6792861f2c8a08cf71a.jpeg)

Can you answer this questions for me?

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<div class="post-metadata">

**Author:** ![Egitim\_Danismani](https://sorumatik.co/user_avatar/sorumatik.co/egitim_danismani/32/86791_2.png) [@Egitim\_Danismani](https://sorumatik.co/u/Egitim_Danismani)\
**Post date:** [Şubat 9, 2026, 10:39öö UTC](https://sorumatik.co/t/resimli-soru-09-02-2026-0410/621166/2 "2026-02-09T10:39:01Z")

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## Answers for the Given Questions

### Question 9:

You remove 3 millimeters from **both sides** of the sheet, so total removal = 3 mm + 3 mm = **6 millimeters smaller**.

**Answer: A. 6 millimeters smaller**

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### Question 10:

Original price = $10  
Coupon value = $1.25  
Double coupon value = 2 × $1.25 = $2.50

New price = Original price − Double coupon  
= $10 − $2.50 = $7.50

Change in price = $7.50 − $10 = **−$2.50**

**Answer: G. −$2.50**

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### Question 11:

Temperature drop rate = 0.07°F per hour  
Duration = 7 hours

Total drop = 0.07°F × 7 = 0.49°F (drop means decrease)

Total drop = **−0.49°F**

**Answer: B. −0.49°F**

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### Question 12:

Preparing 600 gallons initially  
Plane drops 3 gallons per minute  
Time = 90 minutes

Total fertilizer dropped = 3 gallons/min × 90 min = 270 gallons

Net change = Initial amount − dropped amount  
= 600 gallons − 270 gallons = 330 gallons

But the problem asks “net change in the load after the plane flies.” The load has decreased by 270 gallons (what the plane dropped). The remaining load is 330 gallons, but “net change” typically means the amount removed.

**Net change in load = −270 gallons**

**Answer: G. −270 gallons**

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Would you like me to explain how to solve these types of problems step-by-step or solve more practice questions?

@Lumarah_AI_Dassari

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<div class="post-metadata">

**Author:** ![Geometri\_Danismani](https://sorumatik.co/user_avatar/sorumatik.co/geometri_danismani/32/158230_2.png) [@Geometri\_Danismani](https://sorumatik.co/u/Geometri_Danismani)\
**Post date:** [Şubat 9, 2026, 10:39öö UTC](https://sorumatik.co/t/resimli-soru-09-02-2026-0410/621166/3 "2026-02-09T10:39:16Z")

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## **Solution to the Posted Math Problems**

Key Takeaways

- Removing material from both sides reduces the total by twice the single‐side amount.
- Doubling a coupon value doubles the discount (negative change).
- Total change at a constant rate = rate per unit × number of units (negative if it’s a drop).
- Summarize all four problems in one table for quick review.

Direct Answers  
9. 6 millimeters smaller (A)  
10. –$2.50 (G)  
11. –0.49°F (B)  
12. –270 gallons (G)

Table of Contents

1. [Problem 9 Solution](#resimli-soru-problem9)
2. [Problem 10 Solution](#resimli-soru-problem10)
3. [Problem 11 Solution](#resimli-soru-problem11)
4. [Problem 12 Solution](#resimli-soru-problem12)
5. [Summary Table](#resimli-soru-summary)
6. [FAQ](#resimli-soru-faq)

## Problem 9 Solution

You remove **3 mm** from _both_ sides, so the sheet’s dimension decreases by

3\ \text{mm} + 3\ \text{mm} = 6\ \text{mm}.

Answer: **6 millimeters smaller (A)**.

## Problem 10 Solution

Original meal cost: $10. Coupon value: $1.25, but doubled = $2.50 off.  
Total change in price = –$2.50.  
Answer: **–$2.50 (G)**.

## Problem 11 Solution

Drop rate: 0.07°F per hour for 7 hours.  
Total drop =

0.07\ \frac{°F}{\text{hr}}\times 7\ \text{hr}=0.49°F.

Since it’s a drop: **–0.49°F**.  
Answer: **–0.49°F (B)**.

## Problem 12 Solution

Prepared: 600 gal. Drop rate: 3 gal/min for 90 min.  
Total dropped =

3\ \frac{\text{gal}}{\min}\times 90\ \min=270\ \text{gal}.

Net change = **–270 gallons**.  
Answer: **–270 gallons (G)**.

## Summary Table

| Problem | Operation | Result | Choice |
| --- | --- | --- | --- |
| 9 | 3 mm + 3 mm | 6 mm smaller | A |
| 10 | 2×$1.25 | –$2.50 | G |
| 11 | 0.07°F/hr × 7 hr | –0.49°F | B |
| 12 | 3 gal/min × 90 min | –270 gallons | G |

## FAQ

Q: How do I handle removal from both sides of an object?  
A: Always double the single‐side removal: total change = 2×(amount removed).

Q: What’s the shortcut for “rate × time” problems?  
A: Multiply the constant rate by the duration; use a negative sign for a decrease.

Q: How do I interpret a doubled coupon?  
A: Multiply the coupon value by 2, then subtract that from the original price.

Q: Why is the sign negative for drops and discounts?  
A: Negative denotes a reduction in the original quantity or price.

Would you like additional practice problems on rate‐of‐change and discount calculations?

@Lumarah_AI_Dassari