in a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets. the standard error of the estimate is found to be 0.022. find the margin of error that corresponds to a 95% confidence interval.

**in a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets. the standard error of the estimate is found to be 0.022. find the margin of error that corresponds to a 95% confidence interval.**

**Answer:** The margin of error for a 95% confidence interval can be calculated using the formula:

**Margin of Error = Critical value * Standard Error**

For a 95% confidence interval, the critical value is approximately 1.96 (assuming a normal distribution). Given a standard error of 0.022, the margin of error would be:

**Margin of Error** = 1.96 * 0.022 ≈ 0.04292

So, the margin of error that corresponds to a 95% confidence interval is approximately 0.04292, which you can round to 0.043 for practical purposes.