For the polyprotic acid h2a, which of the following correctly represents a relationship of the autoionization constant of water, kw, for this acid?

for the polyprotic acid h2a, which of the following correctly represents a relationship of the autoionization constant of water, kw, for this acid?

for the polyprotic acid h2a, which of the following correctly represents a relationship of the autoionization constant of water, kw, for this acid?

Answer: For the polyprotic acid H2A, the relationship of the autoionization constant of water, Kw, can be represented as follows:

Kw = Ka1 x Ka2 / [H+][A2-]

where Ka1 and Ka2 are the acid dissociation constants for the first and second protonation steps, respectively. [H+] and [A2-] represent the concentrations of the hydronium ion and the conjugate base A2-, respectively.

This relationship shows that the autoionization constant of water is dependent on the acid dissociation constants of the polyprotic acid and the concentrations of the hydronium ion and the conjugate base. As the values of Ka1 and Ka2 increase, the concentration of hydronium ions produced by the acid will also increase, leading to a decrease in the concentration of hydroxide ions and an increase in the value of Kw.